Problem 12. odd_count.js (forloop is introduced)

 /*Question

Given a sequence of integer, count the number of odd number in the sequence.

Input:

First line contains a positive integer, say n , denoting the length of the sequence.

Output:

One line containing an integer, denoting the number of odd numbers in the input sequence.

Example:

Input:

5

8 77 24 22 27

Output:

2

Algorithm:

1. Read the length of the sequence.

2. Read the integer from the sequence.

3. Check whether odd or even, if odd, increment he oddCount variable.

4. Repeat step 3 for every number in the sequence

5. Log the odd count.

*/

let fs = require("fs");

let data = fs.readFileSync(0, 'utf-8');

let idx = 0;

data = data.split('\n');

function readLine() {

idx++;

return data[idx - 1].trim();

}

//..............................................................................................................................

let lengthOfSeq = parseInt(readLine()); // 5

let sequence = readLine().split(" "); // ['8' , '77' , '24' , '22' , '27']

//console.log(sequence);

let odd_Count = 0; // we are assuming initially there are 0 odd numbers

for (let i = 0; i < lengthOfSeq; i++) // 1)i=0<5 ,

{

if (parseInt(sequence[i]) % 2 != 0) //1)8%2 ==0 therefore don't go into if condition and i++, same for other all

{

odd_Count++;

}

}

console.log(odd_Count);

Terminal:

Nobins-MacBook-Pro:STOC_MODULE 11SEPT 2022 nobinpunyo$ node odd_count.js <input.txt 2 Nobins-MacBook-Pro:STOC_MODULE 11SEPT 2022 nobinpunyo$

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