countfirst1.js

 /*Count first

You have been given a sequence of n integers. Lets say the given sequence is a0, a1, a2, a3 ...
an-1.

You need to find the number of occurrences of the first value (i.e. a0) in the given sequence.

Input Format:
First line contains an integer n, denoting the length of the sequence.

Next n lines contains one integer each.

Output Format:
One integer, denoting the result, as mentioned above.

Example:
Input:

5
10
20
30
40
10
Output:

2
Explanation:

First line contains 5, meaning the sequence has 5 integers.
First element is 10.
In the given sequence, 10 occurs 2 times. So, the output is 2.
*/

let fs = require("fs");
let data = fs.readFileSync(0, 'utf-8');
let idx = 0;
data = data.split('\n');

function readLine() {
idx++;
return data[idx - 1].trim();
}
//======================================================================================================

let noOfInputs = parseInt(readLine()); // 5

let firstInteger = parseInt(readLine()); // 10

let count = 1;

for (let i = 1; i <= noOfInputs - 1; i++) {

let num = parseInt(readLine());

if (num == firstInteger) {

count++;
}
}
console.log(count);

///////////////////////////////////////////////////////////////////////////////////////////////
TERMINAL:






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